C Program to Make a Simple Calculator Using switch...case

C Program to Make a Simple Calculator Using switch...case

This program takes an arithmetic operator +, -, *, / and two operands from the user and performs the calculation on the two operands depending upon the operator entered by the user.

// Performs addition, subtraction, multiplication or division depending the input from user

# include <stdio.h>

int main() {

    char operator;

    double firstNumber,secondNumber;

    printf("Enter an operator (+, -, *,): ");

    scanf("%c", &operator);

    printf("Enter two operands: ");

    scanf("%lf %lf",&firstNumber, &secondNumber);

    switch(operator)

    {

        case '+':

            printf("%.1lf + %.1lf = %.1lf",firstNumber, secondNumber, firstNumber + secondNumber);

            break;

        case '-':

            printf("%.1lf - %.1lf = %.1lf",firstNumber, secondNumber, firstNumber - secondNumber);

            break;

        case '*':

            printf("%.1lf * %.1lf = %.1lf",firstNumber, secondNumber, firstNumber * secondNumber);

            break;

        case '/':

            printf("%.1lf / %.1lf = %.1lf",firstNumber, secondNumber, firstNumber / secondNumber);

            break;

        // operator doesn't match any case constant (+, -, *, /)

        default:

            printf("Error! operator is not correct");

    }

    return 0;

}

Output:

Enter an operator (+, -, *,): *

Enter two operands: 1.5

4.5

1.5 * 4.5 = 6.8

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